Count a values' consecutive duplicates in a range

L

loudnoiseman

Board Regular
Joined
Dec 31, 2004
Messages
218
Office Version
  1. 365
Platform
  1. Windows
Hi All,

I'd like to count how many times a numerical value repeats in a range as a consecutive duplicate - I didn't see any related posts...

For example, the value is in A2 and the range is D2:Z2 and I'd like to place the formula in B2 to return the # of consecutive duplicates.

With comma's separating cells, let's say value is 3 and range is: 4,6,8,3,3,5,3,3,8,9,2 etc.

In this short excerpt the result would be 2.

Thanks!!
 

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Try this array formula** :

=SUM(IF(FREQUENCY(IF(D2:Z2=A2,COLUMN(D2:Z2)),IF(D2:Z2<>A2,COLUMN(D2:Z2)))>1,1))

** array formulas need to be entered using the key combination of CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT key then hit ENTER.
 
Upvote 0
try

=SUMPRODUCT(--(D2:Z2=A2),--(E2:AA2=A2),--(F2:AB2<>A2))
 
Upvote 0
Good question Seiya,

the result in your example should be 5 whereas formula suggestions from sanrv1f & #Name? result in 2...

I guess I was hoping for a process that would count all instances where the value is found and the next cell is equal...

hmmm

well, thanks for suggestions
 
Upvote 0
then, remove the last part of my formula

=SUMPRODUCT(--(D2:Z2=A2),--(E2:AA2=A2))
 
Upvote 0
UDF

=CountConsecutive(D2:Z2,3)

Code: 
Function CountConsecutive(ByRef rng As Range, myNum) As Long
Dim a, i As Long
a = rng.Value
For i = 1 To UBound(a, 2) - 1
    If(a(1, i + 1) = myNum) * (a(1, i) = myNum) Then
        CountConsecutive = CountConsecutive + 1
    End If
Next
End Function
 
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